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JEE Advanced 2019
Paper-1 2019
Question
A block of weight 100 N is suspended by copper and steel wires of same cross sectional area $0.5 \mathrm{~cm}^2$ and, length $\sqrt{3} \mathrm{~m}$ and 1 m , respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are $30^{\circ}$ and $60^{\circ}$, respectively. If elongation in copper wire is $\left(\Delta \ell_{\mathrm{C}}\right)$ and elongation in steel wire is $\left(\Delta \ell_{\mathrm{S}}\right)$, then the ratio $\frac{\Delta \ell_{\mathrm{C}}}{\Delta \ell_{\mathrm{S}}}$ is $\_\_\_\_$ . [Young's modulus for copper and steel are $1 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$ and $2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$ respectively]
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Question Tags
JEE Advance
Physics
Easy
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