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JEE MAIN 2023
11-4-2023
Question
A capacitor of capacitance C is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is:
Select the correct option:
A
$\frac{\mathrm{CV}}{2 \varepsilon_0}$
B
$\frac{2 \mathrm{CV}}{\varepsilon_0}$
C
$\frac{\mathrm{CV}}{\varepsilon_0}$
D
Zero
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Sol. $\begin{aligned} \phi & =\frac{q_{\text {in }}}{\epsilon_0} \\ = & \frac{Q}{\epsilon_0}=\frac{C V}{\epsilon_0}\end{aligned}$
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