capacitor capacitance |CARBONYLCARBOXYLDERIVATIVEJEEMain2023

JEE MAIN 2023

11-4-2023

Question

A capacitor of capacitance C is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is:

Select the correct option:

$\frac{\mathrm{CV}}{2 \varepsilon_0}$

$\frac{2 \mathrm{CV}}{\varepsilon_0}$

$\frac{\mathrm{CV}}{\varepsilon_0}$

Zero

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Sol. $\begin{aligned} \phi & =\frac{q_{\text {in }}}{\epsilon_0} \\ = & \frac{Q}{\epsilon_0}=\frac{C V}{\epsilon_0}\end{aligned}$

Question Tags

JEE Main

Chemistry

Easy

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