Car is moving with a constant|CIRCULAR MOTION|JEE-Main 2023

JEE MAINS 2023

25.01.23

Question

A car is moving with a constant speed of 20 m/s in a circular horizontal track of radius 40 m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be :

Select the correct option:

$\frac{\pi}{6}$

$\frac{\pi}{2}$

$\frac{\pi}{4}$

$\frac{\pi}{3}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Ans. (3) Sol. $\mathrm{T} \cos \theta=\mathrm{mg}$ $$ \begin{aligned} & \mathrm{T} \sin \theta=\frac{\mathrm{mv}^2}{\mathrm{R}} \\ & \tan \theta=\frac{\mathrm{v}^2}{\mathrm{Rg}} \\ & \tan \theta=\frac{20^2}{40 \times 10} \\ & \tan \theta=1 \\ & \Rightarrow \quad \theta=\frac{\pi}{4} \end{aligned} $$

Question Tags

JEE Main

Physics

Easy

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