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JEE MAIN 2026
22-01-2026 S1
Question
A circular disc has radius $R_1$ and thickness $T_1$. Another circular disc made of the same material has radius $R_2$ and thickness $T_2$. If the moment of inertia of both discs are same and $\frac{R_1}{R_2}=2$ then $\frac{T_1}{T_2}=\frac{1}{\alpha}$ The value of $\alpha$ is $\_\_\_\_$。
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Question Tags
JEE Main
Physics
Medium
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