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JEE Advance 2017
Paper-1
Multiple correct answers - Select all that apply
Question
A circular insulated copper wire loop is twisted to form two loops of area A and 2A as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane (of the paper). A uniform magnetic field $\vec{B}$ points into the plane of the paper. At $\mathrm{t}=0$, the loop starts rotating about the common diameter as axis with a constant angular velocity $\omega$ in the magnetic field. Which of the following options is/are correct?
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Select ALL correct options:
A
The net emf induced due to both the loops is proportional to $\cos \omega t$
B
The rate of change of the flux is maximum when the plane of the loops is perpendicular to plane of the paper
C
The amplitude of the maximum net emf induced due to both the loops is equal to the amplitude of maximum emf induced in the smaller loop alone
D
The emf induced in the loop is proportional to the sum of the areas of the two loops
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
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Question Tags
JEE Advance
Physics
Easy
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