A coil has an inductance of 2 H and resistance of $4 \Omega$. A 10 V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be $\_\_\_\_$ $\times 10^{-2} \mathrm{~J}$
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Solution
Sol. $I=\frac{V}{R}=\frac{5}{2} A$
$E=\frac{1}{2} L I^2=\frac{1}{2} \times 2 \times\left(\frac{5}{2}\right)^2$
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