A coil is placed | Electromagnetic Induction

JEE MAIN 2022

28-06-22

Question

A coil is placed in a time varying magnetic field. If the number of turns in the coil were to be halved and the radius of wire doubled, the electrical power dissipated due to the current induced in the coil would be: (Assume the coil to be short circuited.)

Select the correct option:

Halved

Quadrupled

The same

Doubled

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & =\frac{\varepsilon^2}{R}=\frac{\left(N A \frac{d B}{d t}\right)^2 \times A_c}{\rho \ell} \\ & P^{\prime}=\frac{\left(\frac{N A}{2} \frac{d B}{d t}\right)^2 \times 4 A_c}{\rho \ell / 2} \\ & \Rightarrow P^{\prime}=2 P\end{aligned}$

Question Tags

JEE Main

Physics

Easy

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