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JEE MAIN 2022
25-06-2022 S1
Question
A force on an object of mass 100 g is $(10 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}) \mathrm{N}$. The position of that object at $t=2 \mathrm{~s}$ is $(a \hat{\mathrm{i}}+b \hat{\mathrm{j}}) \mathrm{m}$ after starting from rest. The value of $\frac{a}{b}$ will be
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Question Tags
JEE Main
Physics
Easy
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