A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air is $\lambda$, calculate the change of microscope's resolving power due to oil and choose the correct option
Select the correct option:
A
Resolving power will be $\frac{1}{4}$ in the oil than it was in the air
B
Resolving power will be twice in the oil than it was in the air.
C
Resolving power will be four times in the oil than it was in the air.
D
Resolving power will be $\frac{1}{2}$ in the oil than it was in the air.
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