A natural number has prime factorization given by $\mathrm{n}=2^{\mathrm{x}} 3^{\mathrm{y}} 5^{\mathrm{z}}$, where y and z are such that $\mathrm{y}+\mathrm{z}=5$ and $\mathrm{y}^{-1}+\mathrm{z}^{-1}=\frac{5}{6}$, $\mathrm{y}>\mathrm{z}$. Then the number of odd divisors of n , including 1 , is:
