A particle is moved along a path AB-BC-CD-DE-EF-FA, as shown in figure, in presence of a force $\overrightarrow{\mathrm{F}}=(\alpha y \hat{\mathrm{i}}+2 \alpha x \hat{\mathrm{j}}) \mathrm{N}$, where x and y are in meter and $\alpha=-1 \mathrm{~N} / \mathrm{m}^{-1}$. The work done on the particle by this force $\overrightarrow{\mathrm{F}}$ will be $\_\_\_\_$ Joule.