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JEE-Main_2024
290124_(S2)
Question
A particle is moving in a straight line. The variation of position ' $x$ ' as a function of time ' $t$ ' is given as $x=\left(t^3-6 t^2+20 t+15\right) m$. The velocity of the body when its acceleration becomes zero is
Select the correct option:
A
$4 \mathrm{~m} / \mathrm{s}$
B
$8 \mathrm{~m} / \mathrm{s}$
C
$10 \mathrm{~m} / \mathrm{s}$
D
$6 \mathrm{~m} / \mathrm{s}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Medium
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