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JEE MAIN 2019
12-01-2019 S2
Question
A particle of mass 20 g is released with an initial velocity $5 \mathrm{~m} / \mathrm{s}$ along the curve from the point A , as shown in the figure. The point $A$ is a height $h$ from point $B$. The particle slides along the frictionless surface. When the particle reaches point $B$, its angular momentum about $O$ will be: $\left(\right.$ Take $\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$
Select the correct option:
A
$2 \mathrm{~kg}-\mathrm{m}^2 / \mathrm{s}$
B
$3 \mathrm{~kg}-\mathrm{m}^2 / \mathrm{s}$
C
$8 \mathrm{~kg}-\mathrm{m}^2 / \mathrm{s}$
D
$6 \mathrm{~kg}-\mathrm{m}^2 / \mathrm{s}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Medium
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