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JEE MAIN 2024
01-02-2024 S2
Question
A particular hydrogen - like ion emits the radiation of frequency $3 \times 10^{15} \mathrm{~Hz}$ when it makes transition from n=2 to n=1. The frequency of radiation emitted in transition from n=3 to n=1 is $\frac{x}{9} \times 10^{15} \mathrm{~Hz}$, when x=_____.
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Solution
$\begin{aligned} & E=-13.6 z^2\left(\frac{1}{n_i^2}-\frac{1}{n_f^2}\right) \\ & \mathrm{E}=\mathrm{C}\left(\frac{1}{\mathrm{n}_{\mathrm{f}}^2}-\frac{1}{\mathrm{n}_{\mathrm{i}}^2}\right) \\ & \mathrm{h} \nu=\mathrm{C}\left[\frac{1}{\mathrm{n}_{\mathrm{f}}^2}-\frac{1}{\mathrm{n}_{\mathrm{i}}^2}\right] \\ & \frac{v_1}{v_2}=\frac{\left[\frac{1}{n_f^2}-\frac{1}{n_i^2}\right]_{2-1}}{\left[\frac{1}{n_f^2}-\frac{1}{n_i^2}\right]_{3-1}} \\ & =\frac{\left[\frac{1}{1}-\frac{1}{4}\right]}{\left[\frac{1}{1}-\frac{1}{9}\right]}=\frac{3 / 4}{8 / 9} \\ & =\frac{3}{4} \times \frac{9}{8} \\ & \frac{v_1}{v_2}=\frac{27}{32} \\ & v_2=\frac{32}{27} v_1=\frac{32}{27} \times 3 \times 10^{15} \mathrm{~Hz}=\frac{32}{9} \times 10^{15} \mathrm{~Hz}\end{aligned}$
Question Tags
JEE Main
Physics
Medium
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