A pendulum is executing SHM... | Simple Harmonic Motion

JEE MAIN 2019

11-01-2019 S2

Question

A pendulum is executing simple harmonic motion and its maximum kinetic energy is $\mathrm{K}_1$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is$$ \mathrm{K}_2 . $$ Then

Select the correct option:

$\mathrm{K}_2=2 \mathrm{~K}_1$

$\mathrm{K}_2=\frac{\mathrm{K}_1}{4}$

$\mathrm{K}_2=\mathrm{K}_1$

$\mathrm{K}_2=\frac{\mathrm{K}_1}{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution