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JEE MAIN 2019
12-04-2019 S2
Question
A plane electromagnetic wave having a frequency $v=23.9 \mathrm{GHz}$ propagates along the positive z-direction in free space. The peak value of the electric field is $60 \mathrm{~V} / \mathrm{m}$. Which among the following is the acceptable magnetic field component in the electromagnetic wave?
Select the correct option:
A
$\vec{B}=60 \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right) \hat{k}$
B
$\vec{B}=2 \times 10^7 \sin \left(0.5 \times 10^3 z+1.5 \times 10^{11} t\right) \hat{i}$
C
$\vec{B}=2 \times 10^{-7} \sin \left(0.5 \times 10^3 z-1.5 \times 10^{11} t\right) \hat{i}$
D
$\vec{B}=2 \times 10^{-7} \sin \left(0.5 \times 10^3 z+0.5 \times 10^{11} t\right) \hat{i}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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