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JEE Advanced 2025 - Mathematics
29-01-2025 SHIFT-2
Question
A poly-atomic molecule ( $C_{V}=3 R, C_{P}=4 R$, where $R$ is gas constant) goes from phase space point $\mathrm{A}\left(\mathrm{P}_{\mathrm{A}}=10^{5} \mathrm{~Pa}, \mathrm{~V}_{\mathrm{A}}=4 \times 10^{-6} \mathrm{~m}^{3}\right)$ to point $\mathrm{B}\left(\mathrm{P}_{\mathrm{B}}=5 \times 10^{4} \mathrm{~Pa}, \mathrm{~V}_{\mathrm{B}}=6 \times 10^{-6} \mathrm{~m}^{3}\right)$ to point $\mathrm{C}\left(\mathrm{P}_{\mathrm{C}}=10^{4} \mathrm{~Pa}, \mathrm{~V}_{\mathrm{C}}=8 \times 10^{-6} \mathrm{~m}^{3}\right) . \mathrm{A}$ to B is an adiabatic path and B to C is an isothermal path. The net heat absorbed per unit mole by the system is :[
Select the correct option:
A
$500 \mathrm{R} \ln 2$
B
$500 \mathrm{R}(\ln 3+\ln 4)$
C
$400 R \ln 4$
D
$450 \mathrm{R}(\ln 4-\ln 3)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Medium
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