A proton and a $\mathrm{Li}^{3+}$ nucleus are accelerated by the same potential. If $\lambda_{\mathrm{Li}}$ and $\lambda_P$ denote the de Broglie wavelengths of $\mathrm{Li}^{3+}$ and proton respectively, then the value of $\frac{\lambda_{\mathrm{Li}}}{\lambda_P}$ is $\times 10^{-}$ ${ }^1$. The value of $x$ is $\_\_\_\_$ . (Rounded off to the nearest integer) (Mass of $\mathrm{Li}^{3+}=8.3$ mass of proton)