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JEE MAIN 2025
22-01-2025 SHIFT-2
Question
A proton is moving undeflected in a region of crossed electric and magnetic fields at a constant speed of $2 \times 10^5 \mathrm{~ms}^{-1}$. When the electric field is switched off, the proton moves along a circular path of radius 2 cm . The magnitude of electric field is $x \times 10^4 \mathrm{~N} / \mathrm{C}$. The value of $x$ is $\_\_\_\_$ Take the mass of the proton $=1.6 \times 10^{-27} \mathrm{~kg}$.
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Question Tags
JEE Main
Physics
Medium
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