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JEE-MAIN 2019
12-01-2019 S1
Question
A simple pendulum, made of a string of length $I$ and a bob of mass $m$, is released from a small angle $\theta 0$. It strikes a block of mass $M$, kept on a horizontal surface at its lowest point of oscillations, elastically. It bounces back and goes up to an angle $\theta_1$. Then M is given by
Select the correct option:
A
$\mathrm{m}\left(\frac{\theta_0+\theta_1}{\theta_0-\theta_1}\right)$
B
$\frac{\mathrm{m}}{2}\left(\frac{\theta_0-\theta_1}{\theta_0-\theta_1}\right)$
C
$\frac{\mathrm{m}}{2}\left(\frac{\theta_0+\theta_1}{\theta_0-\theta_1}\right)$
D
$\mathrm{m}\left(\frac{\theta_0-\theta_1}{\theta_0+\theta_1}\right)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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