A simple pendulum of length 1" " m has a wooden bob of mass 1" " kg. It is struck by a bullet of mass $10^{-2} \mathrm{~kg}$ moving with a speed of $2 \times 10^2 \mathrm{~ms}^{-1}$. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is. (use $\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$ )