A small block starts slipping down from a point B on an inclined plane AB, which is making an
angle $\theta$ with the horizontal section BC is smooth and the remaining section CA is rough with a coefficient of friction $\mu$. It is found that the block comes to rest as it reaches the bottom (point $A$ ) of the inclined plane. If $B C=2 A C$, the coefficient of friction is given by $\mu=\mathrm{k} \tan \theta$. The value of k is $\_\_\_\_$ .
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