A soap bubble is blown to a diameter of 7 cm . 36960erg of work is done in blowing it further. If surface tension of soap solution is 40dyne/ cm then the new radius is $\_\_\_\_$ cm. Take : $\left(\pi=\frac{22}{7}\right)$.
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
