A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is:
Select the correct option:
A
$2.4 \times 10^3 \mathrm{~A} \mathrm{~m}^{-1}$
B
$1.2 \times 10^3 \mathrm{~A} \mathrm{~m}^{-1}$
C
$1 \mathrm{~A} \mathrm{~m}^{-1}$
D
$2.4 \times 10^3 \mathrm{~A} \mathrm{~m}^{-1}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Sol. Magnetic field at centre inside the solenoid is given by
$$
\mathrm{B}=\mu_0 \mathrm{nl}
$$
So magnetic intensity at centre
$$
\begin{aligned}
& \mathrm{H}=\frac{\mathrm{B}}{\mu_0}=\mathrm{nl}=\left(\frac{1200}{2}\right)(2) \\
& \mathrm{H}=1.2 \times 10^3 \mathrm{Am}^{-1}
\end{aligned}
$$
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
