A solid sphere of mass 5 kg... |JEE Main 2026 22 Jan Shift 1

JEE MAIN 2026

22-01-2026 S1

Question

A solid sphere of mass 5 kg and radius 10 cm is kept in contact with another solid sphere of mass 10 kg and radius 20 cm . The moment of inertia of this pair of spheres about the tangent passing through the point of contact is $\_\_\_\_$ $\mathrm{kg} \cdot \mathrm{m}^2$.

Select the correct option:

0.36

0.72

0.18

0.63

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \mathrm{I}=\frac{7}{5}\left[\mathrm{~m}_1 \mathrm{R}_1^2+\mathrm{m}_2 \mathrm{R}_2^2\right] \\ & =\frac{7}{5}\left[5(10)^2+10 \times(20)^2\right] \times 10^{-4} \\ & \mathrm{I}=63 \times 10^{-2} \mathrm{~kg} \mathrm{~m}^2 \\ & \mathrm{I}=0.63 \mathrm{~kg} \mathrm{~m}^2\end{aligned}$

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JEE Main

Physics

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