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JEE MAIN 2019
09-01-19 S2
Question
A solution containing 62 g ethylene glycol in 250 g water is cooled to $-10^{\circ} \mathrm{C}$. If $\mathrm{K}_{\mathrm{f}}$ for water is $1.86 \mathrm{Kkg} \mathrm{mol}^{-1}$, the amount of water (in g ) separated as ice is
Select the correct option:
A
64
B
32
C
16
D
48
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$ \begin{aligned} & \Delta T_f=K_f \times m \\ & \Rightarrow 10=1.86 \times \frac{62 \times 1000}{62 \times w_A} \\ & \Rightarrow \quad w_A=\frac{1.86 \times 1000}{10}=186 \mathrm{~g} \end{aligned} $$ Given amount of $\mathrm{H}_2 \mathrm{O}$ is 250 g ∴ The amount of water separated as ice $$ =250-186=64 \mathrm{~g} $$
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