Physics_JEE_Advance_2015_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE Advance 2015

Paper-2

Multiple correct answers - Select all that apply

Question

A spherical body of radius R consists of a fluid of constant density and is in equilibrium under its own gravity., If $\mathrm{P}(\mathrm{r})$ is the pressure at $\mathrm{r}(\mathrm{r}<\mathrm{R})$, then the correct option(s) is (are)

Select ALL correct options:

$P(r=0)=0$

$\frac{\mathrm{P}(\mathrm{r}=3 \mathrm{R} / 4)}{\mathrm{P}(\mathrm{r}=2 \mathrm{R} / 3)}=\frac{63}{80}$

$\frac{\mathrm{P}(\mathrm{r}=3 \mathrm{R} / 5)}{\mathrm{P}(\mathrm{r}=2 \mathrm{R} / 3)}=\frac{16}{21}$

$\frac{\mathrm{P}(\mathrm{r}=\mathrm{R} / 2)}{\mathrm{P}(\mathrm{r}=\mathrm{R} / 3)}=\frac{20}{27}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

⚠ Partially correct. Some answers are missing.

Solution

Question Tags

JEE Advance

Physics

Easy

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