A table tennis ball has radius $(3 / 2) \times 10^{-2} \mathrm{~m}$ and mass $(22 / 7) \times 10^{-2} \mathrm{~kg}$. It is slowly pushed down into a swimming pool to a depth of $d=0.7 \mathrm{~m}$ below the water surface and then released from rest. It emerges from the water surface at speed $v$, without getting wet, and rises up to a height $H$. Which of the following option(s) is (are) correct|
[Given: $\pi=22 / 7, g=10 \mathrm{~ms}^{-2}$, density of water $=1 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$, viscosity of water $=1 \times 10^{-3} \mathrm{~Pa}-\mathrm{s}$.]
Select ALL correct options:
A
The work done in pushing the ball to the depth d is 0.077 J .
B
If we neglect the viscous force in water, then the speed $v=7 \mathrm{~m} / \mathrm{s}$.
C
If we neglect the viscous force in water, then the height $H=1.4 \mathrm{~m}$.
D
(The ratio of the magnitudes of the net force excluding the viscous force to the maximum viscous force in water is $500 / 9$.
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