Report Issue

JEE MAIN 2021
20-07-2021 - S1
Question
AC voltage V(t) = 20 $\sin \omega t$ of frequency 50 Hz is applied to a parallel plate capacitor. The separation between the plates is 2 mm and the area is $1 \mathrm{~m}^2$. The amplitude of the oscillating displacement current for the applied AC voltage is _______. $\left[\right.$ Take $\left.\varepsilon_0=8.85 \times 10^{-12} \mathrm{~F} / \mathrm{m}\right]$
Select the correct option:
A
$21.14 \mu \mathrm{~A}$
B
$83.37 \mu \mathrm{~A}$
C
$27.79 \mu \mathrm{~A}$
D
$55.58 \mu \mathrm{~A}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Physics
Medium
Start Preparing for JEE with Competishun