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JEE MAIN 2024
31.01.24 S2
Question
An $A C$ voltage $V=20 \sin 200 \pi t$ is applied to a series $L C R$ circuit which drives a current $I= 10 \sin \left(200 \pi \mathrm{t}+\frac{\pi}{3}\right)$. The average power dissipated is: [JEE-Main_310124_(S2)_AC] [Ea\$y]
Select the correct option:
A
21.6 W
B
200 W
C
173.2 W
D
50 W
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Physics
Easy
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