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JEE MAIN 2019
08-04-2019 S1
Question
An alternating voltage $\mathrm{v}(\mathrm{t})=220 \sin 100 \pi \mathrm{t}$ volt is applied to a purely resistive load of $50 \Omega$. The time taken for the current to rise from half of the peak value to the peak value is
Select the correct option:
A
2.2 ms
B
7.2 ms
C
5 ms
D
3.3 ms
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Physics
Medium
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