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JEE MAIN 2019
11-01-2019 S1
Question
An amplitude modulated signal is given by $V(t)=10\left[1+0.3 \cos \left(2.2 \times 10^4 t\right)\right] \sin \left(5.5 \times 10^5 t\right)$. Here $t$ is in seconds. The sideband frequencies (in kHz ) are, [Given $\pi=22 / 7$ ]
Select the correct option:
A
1785 and 1715
B
178.5 and 171.5
C
89.25 and 85.75
D
892.5 and 857.5
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Medium
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