Electrochemistry_JEE Advanced_2024_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE Advance 2024

Paper-2 2024

Multiple correct answers - Select all that apply

Question

An aqueous solution of hydrazine $\left(\mathrm{N}_2 \mathrm{H}_4\right)$ is electrochemically oxidized by $\mathrm{O}_2$, thereby releasing chemical ehergy in the form of electrical energy. One of the products generated from the electrochemical reaction is $\mathrm{N}_2(\mathrm{~g})$. Choose the correct statement(s) about the above process

Select ALL correct options:

$\mathrm{OH}^{-}$ions react with $\mathrm{N}_2 \mathrm{H}_4$ at the anode to form $\mathrm{N}_2(\mathrm{~g})$ and water, releasing 4 electrons to the anode.

At the cathode, $\mathrm{N}_2 \mathrm{H}_4$ breaks to $\mathrm{N}_2(\mathrm{~g})$ and nascent hydrogen released at the electrode reacts with oxygen to form water.

At the cathode, molecular oxygen gets converted to $\mathrm{OH}^{-}$.

Oxides of nitrogen are major by-products of the electrochemical process.

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

⚠ Partially correct. Some answers are missing.

Solution