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JEE MAINS 2024
31.01.24
Question
An artillery piece of mass M_1 fires a shell of mass M_2 horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is
Select the correct option:
A
$M_1 /\left(M_1+M_2\right)$
B
$\frac{M_2}{M_1}$
C
$M_2 /\left(M_1+M_2\right)$
D
$\frac{M_1}{M_2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Ans. (2) Sol. $$ \begin{aligned} & \left|\overrightarrow{p_1}\right|=\left|\overrightarrow{p_2}\right| \\ & \mathrm{KE}=\frac{p^2}{2 M} ; \mathrm{p} \text { same } \\ & \mathrm{KE} \propto \frac{1}{\mathrm{~m}} \\ & \frac{\mathrm{KE}_1}{\mathrm{KE}_2}=\frac{\mathrm{p}^2 / 2 \mathrm{M}_1}{\mathrm{p}^2 / 2 \mathrm{M}_2}=\frac{\mathrm{M}_2}{\mathrm{M}_1} \end{aligned} $$
Question Tags
JEE Main
Physics
Easy
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