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JEE-Main_2024
300124_(S1)
Question
An electric toaster has resistance of 60Ω at room temperature $\left(27^{\circ} \mathrm{C}\right)$. The toaster is connected to a 220 V supply. If the current flowing through it reaches 2.75" " A, the temperature attained by toaster is around : (if $\left.\alpha=2 \times 10^{-4} /{ }^{\circ} \mathrm{C}\right)$
Select the correct option:
A
$694^{\circ} \mathrm{C}$
B
$1235^{\circ} \mathrm{C}$
C
$1694^{\circ} \mathrm{C}$
D
$1667^{\circ} \mathrm{C}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \mathrm{R}_{\mathrm{T}=27}=60 \Omega, R_T=\frac{220}{2.75}=80 \Omega \\ & \mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T}) \\ & 80=60\left[1+2 \times 10^{-4}(\mathrm{~T}-27)\right] \\ & \mathrm{T} \approx 1694^{\circ} \mathrm{C}\end{aligned}$
Question Tags
JEE Main
Physics
Medium
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