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JEE MAIN 2023
01-02-2023 S2
Question
An electron of a hydrogen like atom, having $Z=4$, jumps from $4^{\text {th }}$ energy state to $2^{\text {nd }}$ energy state, The energy released in this process, will be: (Given Rch $=13.6 \mathrm{eV}$ ) Where $\mathrm{R}=$ Rydberg constant, $\mathrm{c}=$ Speed of light in vacuum, $\mathrm{h}=$ Planck's constant
Select the correct option:
A
13.6 eV
B
10.5 eV
C
3.4eV
D
40.8 eV
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Solution
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Question Tags
JEE Main
Physics
Easy
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