An electron of mass... |MODERN PHYSICS|JEE-Main 2021

JEE MAIN 2021

25-02-2021 S2

Question

An electron of mass me and a proton of mass $m_p= 1836 \mathrm{~m}_{\mathrm{e}}$ are moving with the same speed. The ratio of their de Broglie wavelength $\frac{\lambda_{\text {electron }}}{\lambda_{\text {proton }}}$ will be

Select the correct option:

1836

918

$\frac{1}{1836}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\frac{\lambda_e}{\lambda_p}=\frac{\frac{\mathrm{h}}{\mathrm{m}_e v}}{\frac{\mathrm{~h}}{\mathrm{~m}_{\mathrm{p}} v}}=1836$

Question Tags

JEE Main

Physics

Easy

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