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JEE MAIN 2025
02-04-2025 SHIFT-2
Question
An electron with mass ' m ' with an initial velocity $(t=0) \vec{v}=v_{0} \hat{i}\left(v_{0}>0\right)$ enters a magnetic field $\vec{B}=B_{0} \hat{j}$. If the initial de-Broglie wavelength at $\mathrm{t}=0$ is $\lambda_{0}$ then its value after time ' t ' would be :
Select the correct option:
A
$\lambda_{0}$
B
$\frac{\lambda_{0}}{\sqrt{1+\frac{e^{2} B_{0}^{2} t^{2}}{m^{2}}}}$
C
$\frac{\lambda_{0}}{\sqrt{1-\frac{e^{2} B_{0}^{2} t^{2}}{m^{2}}}}$
D
$\lambda_{0} \sqrt{1+\frac{e^{2} B_{0}^{2} t^{2}}{m^{2}}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Magnetic field does not work
∴ Speed will not charge, so De-Broglie wavelength remains same.
Question Tags
JEE Main
Physics
Easy
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