An LPG cylinder contains gas at a pressure of 300 kPa at $27^{\circ} \mathrm{C}$. The cylinder can withstand the pressure of $1.2 \times 10^6 \mathrm{~Pa}$. The room in which the cylinder is kept catches fire.
The minimum temperature at which the bursting of cylinder will take place is $\_\_\_\_$ ${ }^{\circ} \mathrm{C}$. (Nearest integer)
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