Aqueous HCl reacts with $\mathrm{MnO}_2(\mathrm{~s})$ to form $\mathrm{MnCl}_2(\mathrm{aq}), \mathrm{Cl}_2(\mathrm{~g})$ and $\mathrm{H}_2 \mathrm{O}(l)$. What is the weight (in g ) of $\mathrm{Cl}_2$ liberated when 8.7 g of $\mathrm{MnO}_2(\mathrm{~s})$ is reacted with excess aqueous HCl solution ? (Given Molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{Mn}=55, \mathrm{Cl}=35.5, \mathrm{O}=16, \mathrm{H}=1$ )