At 298.2 K the relationship | Hydrogen

JEE MAIN 2021

25-07-21 S1

Question

At 298.2 K the relationship between enthalpy of bond dissociation (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) for hydrogen (EH) and its isotope, deuterium ( $\mathrm{E}_{\mathrm{D}}$ ), is best described by:

Select the correct option:

$E_H=\frac{1}{2} E_D$

$E_H=E_D$

$E_H \simeq E_D-7.5$

$E_H=2 E_D$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Medium

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