At time $\mathrm{t}=0$, terminal A in the circuit shown in the figure is connected to B by a key and alternating current $\mathrm{I}(\mathrm{t})=\mathrm{I}_0 \cos (\omega \mathrm{t}$,$) , with \mathrm{I}_0=1 \mathrm{~A}$ and $\omega=500 \mathrm{rad} \mathrm{s}^{-1}$ starts flowing in it with the initial direction shown in the figure. At $t=\frac{7 \pi}{6 \omega}$, the key is switched from B to D. Now onwards on ly A and D are connected. A total charge Q flows from the battery to charge the capacitor fully. If $\mathrm{C}=20 \mu, \mathrm{R}=10 \Omega$ and the battery is ideal with emf of 50 V , identify the correct statement (s)