Electrochemistry | JEE Main 2025 Solution

JEE MAIN 2025

24-01-2025 SHIFT-2

Question

Based on the data given below :
$\begin{array}{ll}\mathrm{E}_{\mathrm{Cr}_2 \mathrm{O}_7^{2-} / \mathrm{Cr}^{3+}}^{\circ}=1.33 \mathrm{~V} & \mathrm{E}_{\mathrm{C}_2 / \mathrm{Cl}^{(-)}}^{\circ}=1.36 \mathrm{~V} \\ \mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^{\circ}=1.51 \mathrm{~V} & \mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\circ}=-0.74 \mathrm{~V}\end{array}$
the strongest reducing agent is :

Select the correct option:

$\mathrm{Cl}^{-}$

$\mathrm{Mn}^{2+}$

$\mathrm{MnO}_{4}^{-}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

For strongest reducing agent
Reduction potential should be lowest
Hence Cr is the strongest reducing agent.
Options (1)

Question Tags

JEE Main

Chemistry

Easy