Let $x=x(y)$ be the solution of the differential equation ${{y}^{2}}~\text{d}x+\left( {x-\frac{1}{y}} \right)\text{d}y=0$. If $x(1)=1$, then $x\left( {\frac{1}{2}} \right)$ is :
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
