By usual analysis, 1.00 g of compound $(\mathrm{X})$ gave 1.79 g of magnesium pyrophosphate. The percentage of phosphorus in compound $(\mathrm{X})$ is : (nearest integer)
(Given, molar mass in $\mathrm{g} \mathrm{mol}^{-1}: \mathrm{O}=16, \mathrm{Mg}=24, \mathrm{P}=31$ )
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