Contact us
Back

Report Issue

Binomial Theorem

Get chapter-wise JEE Main & Advanced questions with solutions

Q JEE-Main 2024
In the expansion of $(1+x)\left(1-x^2\right)\left(1+\frac{3}{x}+\frac{3}{x^2}+\frac{1}{x^3}\right)^5, x \neq 0$, the sum of the coefficient of $x^3$ and $x^{-13}$ is equal to
JEE Main Mathematics Medium
View Solution →
Q JEE-Main 2024
If the Coefficient of $x^{30}$ in the expansion of $\left(1+\frac{1}{x}\right)^6\left(1+x^2\right)^7\left(1-x^3\right)^8 ; x \neq 0$ is $\alpha$, then $|\alpha|$ equals
JEE Main Mathematics Hard
View Solution →
Q JEE MAIN
If $\frac{{ }^{11} \mathrm{C}_1}{2}+\frac{{ }^{11} \mathrm{C}_2}{3}+\cdots \cdot+\frac{{ }^{11} \mathrm{C}_9}{10}=\frac{\mathrm{n}}{\mathrm{m}}$ with $\operatorname{gcd}(\mathrm{n}, \mathrm{m})=1$, then n+m is equal to
JEE Main Mathematics Easy
View Solution →
Q JEE MAIN 2024
If A denotes the sum of all the coefficients in the expansion of $\left(1-3 x+10 x^2\right)^n$ and B denotes the sum of all the coefficients...
JEE Main Mathematics Easy
View Solution →
Q JEE MAIN 2024
${ }^{n-1} C_r=\left(k^2-8\right)^n C_{r+1}$ if and only if :
JEE Main Mathematics Hard
View Solution →
Q JEE MAIN 2025
The remainder, when $7^{103}$ is divided by 23 , is equal to :
JEE Main Mathematics Easy
View Solution →
Q JEE MAIN 2025
Let the coefficients of three consecutive terms $T_{r}, T_{r+1}$ and $T_{r+2}$ in the binomial expansion of $(a+b)^{12}$ be in a G.P. and let $p$ be...
JEE Main Mathematics Easy
View Solution →
Q JEE MAIN 2025
The remainder when ${\left( {{{(64)}^{(64)}}} \right)^{(64)}}$ is divided by 7 is equal to
JEE Main Mathematics Hard
View Solution →
Q JEE MAIN 2025
In the expansion of ${\left( {\sqrt[3]{2} + \frac{1}{{\sqrt[3]{3}}}} \right)^n},n \in \;{\rm{N}}$ , if the ratio of ${15^{{\rm{th }}}}$ term from the beginning to the $...
JEE Main Mathematics Easy
View Solution →
Q JEE MAIN 2025
For an integer $n \ge 2$, if the arithmetic mean of all coefficients in the binomial expansion of ${(x + y)^{2n - 3}}$ is 16...
JEE Main Mathematics Medium
View Solution →