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Chemical Kinetics

Get chapter-wise JEE Main & Advanced questions with solutions

Q JEE MAIN 2022
For a first order reaction $A \rightarrow B$, the rate constant, $\mathrm{k}=5.5 \times 10^{-14} \mathrm{~s}^{-1}$ . The time required for 67% completion of reaction is...
JEE Main Chemistry Easy
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Q JEE MAIN 2022
The activation energy of one of the reactions in a biochemical process is 532611 J $\mathrm{mol}^{-1}$. When the temperature falls from 310 K to 300...
JEE Main Chemistry Medium
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Q JEE-Main 2022
The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700 1000 K . The data has been analysed by plotting...
JEE Main Chemistry Easy
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Q JEE MAIN 2022
The rate constant for a first order reaction is given by the following equation: $\ln \mathrm{k}=33.24-\frac{2.0 \times 10^4 \mathrm{~K}}{\mathrm{~T}}$ The Activation energy for the reaction...
JEE Main Chemistry Easy
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Q JEE MAIN 2022
A flask is filled with equal moles of A and B. The half lives of A and B are 100 s and 50 s respectively...
JEE Main Chemistry Medium
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Q JEE MAIN 2022
For a given chemical reaction
$\gamma_1 A+\gamma_2 B \rightarrow \gamma_3 C+\gamma_4 D$
Concentration of C changes from 10 mmol $\mathrm{dm}^{-3}$ to 20 mmol...
JEE Main Chemistry Medium
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Q JEE MAIN 2024
The following data were obtained during the first order thermal decomposition of a gas A at constant volume:
JEE Main Chemistry Medium
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Q JEE MAIN 2024
$\mathrm{r}=\mathrm{k}[\mathrm{A}]$ for a reaction, $50 \%$ of A is decomposed in 120 minutes. The time taken for $90 \%$ decomposition of $A$ is $\_\_\_\_$ minutes.
JEE Main Chemistry Easy
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Q JEE MAIN 2024
$\mathrm{NO}_2$ required for a reaction is produced by decomposition of $\mathrm{N}_2 \mathrm{O}_5$ in $\mathrm{CCl}_4$ as by equation $2 \mathrm{~N}_2 \mathrm{O}_{5(\mathrm{~g})} \rightarrow 4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
The initial...
JEE Main Chemistry Easy
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Q JEE MAIN 2024
The half-life of radioisotopic bromine - 82 is 36 hours. The fraction which remains after one day is $\times 10^{-2}$. (Given antilog $0.2006=1.587$ )
JEE Main Chemistry Medium
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