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QJEE MAIN 2023
Let the foot of perpendicular from the point $\mathrm{A}(4,3,1)$ on the plane $\mathrm{P}: \mathrm{x}-\mathrm{y}+2 \mathrm{z}+3=0$ be N . If $\mathrm{B}(5, \alpha$, $\beta$ ), $...
JEE MainMathematicsMedium
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QJEE-Main 2023
The area of the quadrilateral ABCD with vertices A(2, 1, 1), B(1, 2, 5), C(–2, –3, 5) and D(1, –6, –7) is equal to
JEE MainMathematicsEasy
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QJEE MAIN 2023
Let the line $=\frac{x}{1}=\frac{6-y}{2}=\frac{z+8}{5}$ intersect the lines $\frac{x-5}{4}=\frac{y-7}{3}=\frac{z+2}{1}$ and $\frac{x+3}{6}=\frac{3-y}{3}=\frac{z-6}{1}$ at the points $A$ and $B$ respectively. Then the distance of the mid-point of the...
JEE MainPhysicsMedium
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QJEE MAIN 2023
If the lines and intersect, then the magnitude of the minimum value of 8is _________.
JEE MainMathematicsMedium
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QJEE MAIN 2023
Let for a triangle ABC , $$ \begin{aligned} & \overrightarrow{\mathrm{AB}}=-2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+3 \hat{\mathrm{k}} ; \\ & \overrightarrow{\mathrm{CB}}=\alpha \hat{\mathrm{i}}+\beta \hat{\mathrm{j}}+\gamma \hat{\mathrm{k}} \\ & \overrightarrow{\mathrm{CA}}=4 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+\delta \hat{\mathrm{k}}...
JEE MainMathematicsEasy
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QJEE MAIN 2023
Let the line L pass through the point $(0,1,2)$, intersect the line $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and be parallel to the plane $2 x+y-3 z=4$. Then the distance...
JEE MainMathematicsHard
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QJEE MAIN 2023
Let N be the foot of perpendicular from the point P(1, –2, 3) on the line passing through the points (4, 5, 8) and (1,...
JEE MainMathematicsMedium
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QJEE MAIN 2023
If the points $P$ and $Q$ are respectively the circumcentre and the orthocentre of a $\triangle A B C$, then $\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}+\overrightarrow{\mathrm{PC}}$ is equal to
JEE MainMathematicsEasy
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QJEE MAIN 2023
Let $\vec{a}=2 \hat{i}+7 \hat{j}-\hat{k}, \vec{b}=3 \hat{i}+5 \hat{k}$ and $\vec{c}=\hat{i}-\hat{j}+2 \hat{k}$. Let $\vec{d}$ be a vector which is perpendicular to both $\vec{a}$ and $\vec{b}$, and $...
JEE MainMathematicsMedium
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QJEE MAIN 2023
Let $|\vec{a}|=2,|\vec{b}|=3$ and the angle between the vectors $\vec{a}$ and $\vec{b}$ be $\frac{\pi}{4}$. Then $|(\vec{a}+2 \vec{b}) \times(2 \vec{a}-3 \vec{b})|^2$ is equal to
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