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QJEE Main 2019
Let $\vec{a}=\vec{i}-\vec{j}, \vec{b}=\vec{i}+\vec{j}+\vec{k}$ and $\vec{c}$ be a vector such that $\vec{a} \times \vec{c}+\vec{b}=\overrightarrow{0}$ and $\vec{a} \cdot \vec{c}=4$, then $|\vec{c}|^2$ is equal to:
JEE MainMathematicsEasy
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QJEE MAIN 2021
Let $\vec{a}-=2 \hat{i}-\hat{j}+2 \hat{k}$ and $\vec{b}=\hat{i}--2 \hat{j}-\hat{k}$. Let a vector $\vec{v}$ be in the plane containing $\vec{a}$ and $\vec{b}$. If $\vec{v}$ is perpendicular to the...
JEE MainMathematicsMedium
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QJEE MAIN 2021
The distance of line 3y – 2z – 1 = 0 = 3x – z + 4 from the point (2, – 1, 6) is...
JEE MainMathematicsMedium
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Q_JEE MAIN_2021
Let $\vec{p}=2 \hat{i}+3 \hat{j}+\hat{k}$ and $\vec{q}=\hat{i}+2 \hat{j}+\hat{k}$ be two vectors. If a vector $\vec{r}=(\alpha \hat{i}+\beta \hat{j}+\gamma \hat{k})$ is perpendicular to each of the vectors $(\bar{p}+\bar{q})$...
JEE MainMathematicsMedium
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Q_JEE MAIN_2021_
Let the foot of perpendicular from a point $P(1,2,-1)$ to the straight line $L: \frac{x}{1}=\frac{y}{0}=\frac{z}{-1}$ be $N$. Let a line be drawn from $P$ parallel...
JEE MainMathematicsMedium
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QJEE MAIN 2021
Let the acute angle bisector of the two planes x – 2y – 2z + 1 = 0 and 2x – 3y – 6z +...
JEE MainMathematicsMedium
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QJEE MAIN 2021 S2
The distance of the point $\mathrm{P}(3,4,4)$ from the point of intersection of the line joining the points. $\mathrm{Q}(3,-4,-5)$ and $R(2,-3,1)$ and the plane $2 x+y+z=7$,...
JEE MainMathematicsEasy
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Q JEE MAIN 2021 S2
Let $\vec{a}=\hat{i}-\alpha \hat{j}+\beta \hat{k}, \vec{b}=3 \hat{i}+\beta \hat{j}+\alpha \hat{k}$ and $\vec{c}=-\alpha \hat{i}+2 \hat{j}+\hat{k}$, where $\alpha$ and $\beta$ are integers. If $\vec{a} \cdot \vec{b}=-1$ and $...
JEE MainMathematicsMedium
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QJEE MAIN 2021 S2
Let $\vec{a}, \vec{b}$ and $\vec{c}$ be three vectors such that $\vec{a}=\vec{b} \times(\vec{b} \times \vec{c})$. If magnitudes of the vectors $\vec{a}, \vec{b}$ and $\vec{c}$ are $...
JEE MainMathematicsMedium
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QJEE MAIN 2021 S2
For real numbers $\alpha$ and $\beta \neq 0$, if the point of intersection of the straight lines $\frac{x-\alpha}{1}=\frac{y-1}{2}=\frac{z-1}{3}$ and $\frac{x-4}{\beta}=\frac{y-6}{3}=\frac{z-7}{3}$, lies on the plane $...
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