The equation k = (6.5 × 10¹² s... | JEE Main 2022

JEE MAIN 2022

29-06-2022 S2

Question

The equation
$$ k=\left(6.5 \times 10^{12} \mathrm{~s}^{-1}\right) \mathrm{e}^{-28000 \mathrm{kJT}} $$ is followed for the decomposition of compound A .
The activation energy for the reaction is $\_\_\_\_$ $\mathrm{kJ} \mathrm{mol}{ }^{-1}$. [nearest integer]
(Given: $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )

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Solution

$\begin{aligned} & \mathrm{K}=\mathrm{Ae}^{-} \mathrm{Ea} / \mathrm{RT}=\left(6.5 \times 10^{12} \mathrm{~s}^{-1}\right) \mathrm{e}^{-26000 \mathrm{KT}} \\ & \frac{\mathrm{Ea}}{8.314}=26000 \\ & \mathrm{Ea}=216.164 \mathrm{~kJ} / \mathrm{mol} .\end{aligned}$

Question Tags

JEE Main

Chemistry

Easy

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